Loksewa · Geotechnical Engineering · Chapter 5

Effective Stress

The soil skeleton never carries the full load alone. Here is how water and grains share the weight above them — and why that quiet arithmetic controls strength, settlement and stability.

01 · The core question

Why effective stress matters

Picture placing a 100 kN load on the ground. Does the soil skeleton carry all 100 kN of it? No — part of that load is carried by the water sitting in the voids, and the rest is carried by the soil particles themselves. The portion carried by the particle skeleton is what we call effective stress, and it is the part that actually governs how the ground behaves.

water
soil skeleton
The applied load splits between pore water and the grain skeleton — only the grain share is "effective".
02 · Vocabulary

Three types of stress in soil

Total stress

σ

The total load per unit area acting at a point in the soil, carried jointly by water and grains.

σ = γ × z

γ = unit weight of soil, z = depth

Pore water pressure

u

The pressure exerted by water sitting in the voids. Above the water table (ignoring capillary effects), it is approximately zero.

u = γw × h

γw ≈ 9.81 kN/m³ (often taken as 10), h = depth below water table

Effective stress

σ′

The stress transmitted through the soil particles. It controls shear strength, settlement, bearing capacity, compressibility and slope stability.

σ′ = σ − u

Terzaghi's Principle

03 · Try it yourself

Terzaghi's Effective Stress Principle

Karl Terzaghi's relationship, σ′ = σ − u, is one of the most important equations in geotechnical engineering. Drag the sliders below to move the water table and the point of interest, and watch the three stresses respond live.

Interactive soil column

WT
Total σ0
Pore u0
Effective σ′0

Assumes γdry = 18, γsat = 20, γw = 9.81 kN/m³. Notice: raise the water table and effective stress falls immediately — even though total stress barely changes.

04 · Worked examples

Putting the numbers together

Example 1 — dry layer

A soil layer is 5 m thick, unit weight = 18 kN/m³, and the water table is below the layer. Find the total stress at the bottom.

No pore pressureu = 0
Total stressσ = 18 × 5 = 90 kPa
Effective stressσ′ = 90 kPa

Example 2 — below the water table

A point is 4 m below the groundwater table. Saturated unit weight = 20 kN/m³, water unit weight = 10 kN/m³.

Step 1: Total stressσ = 20 × 4 = 80 kPa
Step 2: Pore pressureu = 10 × 4 = 40 kPa
Step 3: Effective stressσ′ = 80 − 40 = 40 kPa
05 · Cause and effect

Effect of the water table

The water table strongly influences effective stress. Tap either state below.

Pore water pressure increases.
  • Effective stress decreases.
  • Shear strength decreases.
  • Settlement characteristics change.
Pore water pressure decreases.
  • Effective stress increases.
  • Soil becomes stronger.
06 · Capillary rise

Water climbing against gravity

Water can rise above the groundwater table through small pores due to surface tension. This height is the capillary rise. Finer soils have higher capillary rise because of smaller pore spaces.

SoilApproximate rise
GravelNegligible
Coarse sand0.05 – 0.30 m
Fine sand0.30 – 1.50 m
Silt1 – 5 m
ClayUp to 10 m or more

Engineering importance: causes dampness in buildings, increases foundation moisture, influences frost action, and affects pavement performance.

07 · A failure mode

Quicksand (boiling) condition

When upward seepage force equals the submerged weight of the soil, particles lose contact with each other and the soil behaves like a liquid. This is called quicksand, boiling, or hydraulic failure — it is a seepage phenomenon, not "ordinary sand behaving magically."

Critical hydraulic gradient ic = (Gs − 1) / (1 + e)

Gs = specific gravity of solids, e = void ratio. If the actual hydraulic gradient exceeds ic, quicksand conditions may develop.

Consequences: failure of excavation bottoms, uplift of foundation bases, instability near sheet piles, piping beneath dams.

Prevention: dewatering systems, cutoff walls, sheet piles, relief wells, filter layers, reducing the hydraulic gradient.

08 · Check yourself

Common Loksewa MCQs

09 · Go deeper

Interview questions

Memory box

σ = γz
Total stress
u = γwh
Pore water pressure
σ′ = σ − u
Effective stress
ic = (Gs−1)/(1+e)
Critical hydraulic gradient
WT ↑ → σ′ ↓
Water table rises
WT ↓ → σ′ ↑
Water table falls

Quicksand occurs when upward seepage reduces effective stress to nearly zero. Effective stress governs strength, settlement and bearing capacity.

Study tip

From this point onward, almost every major geotechnical topic — consolidation, shear strength, bearing capacity, earth pressure, and slope stability — uses the concept of effective stress. Make sure you can derive and apply σ′ = σ − u without hesitation.